With three pawns ready to promote, White seems sure to win. But after
1.Rh5+
comes
1...Kg3!!
and Black can draw. [The main variation that Chernev gives is 1...Kxh5?
which loses to 2.Nf4+
Kh6
3.g8N+
. Chernev gives the conclusion as 3...Kh7
4.Ngf6+
Kh6
5.Nxg4+
Kh7
6.Nef6+
Kg7
7.Ne6+
Kf7
8.d8N+
Ke7
9.c8N#
and White ends with five knights on the board.]
2.Rh1
Chernev stops at this point without comment. Apparently he believes that this move stops Black from getting a queen and therefore White wins. But the position can be drawn as follows:
2...Be4!
3.g8Q
[Also drawing is 3.Nf4
Bxh1
4.Ne2+
Kf2
5.g8Q
Kxe2
6.Qxg4+
Bf3
7.Qe6+
Be4
8.d8Q
c1Q
9.Qg4+
Bf3
10.Qe6+
Be4=
; No better is 3.Nc3
Bxh1
4.g8Q
(Or 4.d8Q
c1N+!!
(4...c1Q??
5.Ne2+
) 5.Ka1
Ncb3+
6.Ka2
Nc1+
draw by perpetual check; But not 4.c8Q??
c1Q
and Black has a forced mate: 5.Qb8+
Kh3
6.d8Q
Qc2+
7.Ka1
Qxc3+
8.Ka2
Qc4+
9.Ka1
Nb3+
10.Qxb3+
Qxb3
11.Qd2
Bd5
12.Qh6+
Kg3
13.Qd2
Bd4+
14.Qxd4
Qa2#
)) 4...Bf3
5.Ne4+
Bxe4
6.d8Q
c1Q
transposes to our main line]
3...Bxh1
4.Nc3
Bf3
5.Ne4+!
[After 5.c8Q?!
c1Q
6.Qb8+
Kg2
7.d8Q
it is Black, despite the three White queens, who has the advantage! For example: 7...Qc2+
8.Ka1
Qxc3+
9.Ka2
Bb4
and White's position is dire, but he should be able to draw.]
5...Bxe4
6.d8Q
c1Q
and now Black's threat to mate at b2 leads to
7.Qxg4+
Kxg4
8.c8Q+
Kf3
9.Qf6+
Ke2
10.Qg4+
Ke1
11.Qfh4+
Kf1
12.Qhh3+
Ke1
13.Qhh4+
etc. (Correction by Charles Sullivan, 2007) 1/2-1/2